the bus starting from rest moves with uniform acceleration of ms-2 for 5 minutes find?
a. the speed acquired
b. the distance travelled
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a. the speed acquired
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Answer:
a) 12m/s. b) 720m
Explanation:
a) Initial speed of the bus u=0 (since the bus is initialy at rest)
Time taken, t=2min = 120s
Let v be the final speed acquired by the bus
a=v-u/t
o.1=v-0/120
v=12m/s
b) According to the third equation of motion: v2-v^2=2as
Where s is distance covered by the bus (12)^2-(0)^2=2(0.1)s
s=720m
Distance travelled is 720m
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