Question

The buzzing sound from a mosquito is produced when a vibrates wings
average rate of 600 vibrations per second.when is the time period of the vibrations of each wing​

Answer 1

Answer:

Explanation: Hi!

The average rate of 600 vibrations per second here is the frequency in hertz with which the mosquito moves its wings.

Let 'f' denote the frequency and 't' denote the time period of vibrations.

We have the frequency-time period relation as: f=1/t.

Here f=60 Hz

t= 1/f=1/600=0.0016666666666667 second per vibration.

I hope that answers your question

Answer 2

The time period of the vibrations of each wing​ is $1.67\times 10^{-3}\ s$.

Explanation:

It is given that,

The buzzing sound from a mosquito is produced when a vibrates wings  average rate of 600 vibrations per second.

To find,

Time period of the vibrations of each wing

Formula used,

$T=\dfrac{1}{f}$

f is the frequency

Solution,

Number of vibrations per second is called frequency of a wave. The inverse of the frequency of an object is equal to its time period such that,

$T=\dfrac{1}{f}$

$T=\dfrac{1}{600}$

$T=1.67\times 10^{-3}\ s$

So, the time period of the vibrations of each wing​ is $1.67\times 10^{-3}\ s$. Hence, this is the required solution.

Learn more,

Frequency

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