The % by mass of the element in a compound of molar mass 18g/mol is 11.12, the number of gram of the respective element present in 1mol the compound is
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Answer:
(i) Molecular mass of H2O = 2(1.008 amu) + 16.00 amu=18.016 amu
(ii) Molecular mass of CO2= 12.01 amu + 2 x 16.00 amu = 44.01 amu
(iii) Molecular mass of CH4= 12.01 amu + 4 (1.008 amu) = 16.042 amu
Question 2. Calculate the mass percent of different elements present in sodium sulphate (Na2 SO4).
Answer:
ncert-solutions-for-class-11-chemistry-chapter-1-some-basic-concepts-of-chemistry-1
ncert-solutions-for-class-11-chemistry-chapter-1-some-basic-concepts-of-chemistry-2
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