Question

The C.G. of a wire bend forming a quarter circular arc with radius 10cm is

Answer 1

Answer: 4.24 cm

Step-by-step explanation:

Given:

radius(r)=10 cm

we know that,

center of gravity(c.g.) of quarter circle

$x=y=\frac{4r}{3\pi }$

$x=y=\frac{4(10)}{3\pi }$

x = y = 4.24 cm