Question

the c. g. of three particles placed at the vertices of triangle is acts​

Answer 1

Answer:

Correct option is

C

aGM,2Π3GMa3

As per the figure on the left hand side.

Resultant Gravitational force acting on each particle is:

F=(a2Gm2)2+(a2Gm2)2+2(a2Gm2)(a2Gm2)cos60=3a2Gm2

As per figure on right side, as the particles are expected to move in a circle of radius r (say) while maintaining original separation a,

ra/2=cos30

r=3a

Because of circular motion, the centripetal force is balanced by resultant gravitational force. 

If v is the velocity:

rmv2=3a2