the c. g. of three particles placed at the vertices of triangle is acts
Answers
Answered by
3
Answer:
Correct option is
C
aGM,2Π3GMa3
As per the figure on the left hand side.
Resultant Gravitational force acting on each particle is:
F=(a2Gm2)2+(a2Gm2)2+2(a2Gm2)(a2Gm2)cos60=3a2Gm2
As per figure on right side, as the particles are expected to move in a circle of radius r (say) while maintaining original separation a,
ra/2=cos30
r=3a
Because of circular motion, the centripetal force is balanced by resultant gravitational force.
If v is the velocity:
rmv2=3a2
Similar questions