Question

The C.N. of a M2+ in MX2 is 8. Hence, C.N.
of X– is

Answer 1

The coordination no of X⁻ is 4.

- Each M²⁺ ion is in cubic coordination with eight X⁻ neighbors.

- So the coordination no of each M²⁺ ion is 8.

- Whereas each X⁻ ion is tetrahedrally surrounded by four M²⁺ ions.

- Hence, the coordination no of each X⁻ ion is 4.

- The example of such a structure is Calcium Fluorite (CaF₂).

- Here, the coordination number of Ca²⁺ ion is 8 and the coordination number of X⁻ is 4.

Answer 2

Answer:

4 will be the answer of this question