Question

the c. s. a. hollow silender is ..... ​

Answer 1

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Let the inner and outer radius of the cylinder be r and R

Outer CSA = 2πRh

Inner CSA = 2πrh

Therefore,

CSA of cylinder = Outer CSA + Inner CSA

                           = 2πRh + 2πrh

                           = 2πh(R + r)

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Answer 2

Answer:

Step-by-step explanation:

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