The cab Charges ₹50 for the 1st km and ₹25 for every subsequent kilometre write a linear equation for this information if the total cab Charges were a)
1) ₹670
2) ₹970
3) ₹900
B) what would be the cab Charges if the passenger traveled
1) 40km
2) 25km
3) 50 km
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Answer:
Answer:
324
Step-by-step explanation:
Fare of first two km is 50
Subsequent distance fare is 16
Total distance is x
Total fare is y
y=2*50+16(x-2)
y=100+16x-32
y=68+16x
Fare of 16 km
put the value of x=16
y=68+16*16
y=68+256
y=324
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