Question

The calculated spin only magnetic moment of Cr2+ ion is:. 1. 5.92.BM 2. 2.84BM. 3. 3.87BM. 4. 4.90BM​

Answer 1

$\bigstar$ Given

Cr²⁺ ion

$\bigstar$ To Find

Spin only magnetic moment of Cr²⁺ ion

$\bigstar$ Solution

We know that

$\sf \longrightarrow \mu=\sqrt{n(n+2)} \ B.M$

Here

μ = spin only magnetic moment

n = number of unpaired electrons

According to the question

We are asked to find the spin only magnetic moment of Cr²⁺ ion

Given that

Cr²⁺ ion

Hence

The number of unpaired electrons in

Cr²⁺ ion = 4

Therefore

n = 4

Substituting the values

We get

$\sf \longrightarrow \mu=\sqrt{4(4+2)} \ B.M$

On further simplification

We get

$\sf \longrightarrow \mu=4.89 \ B.M$

$\sf \longrightarrow \mu \approx 4.90 \ B.M$

Therefore

Spin only magnetic moment = 4.90 B.M

Hence

$\checkmark$ Option (4) is correct