Question

The calculated spin only magnetic moments
(BM) of the anionic and cationic species of
[Fe(H20)612 and [Fe(CN)6], respectively, are
(JEE Main 2019,8 April Shift-II]
(a) O and 4.9
(b) 2.84 and 5.92
(c) O and 5.92
(d) 4.9 and 0​

Answer 1

Answer:

the answer is your question is 0 and 4.9

and this is a correct answer

Answer 2

Explanation:

(Fe(H20)6)2 has 4 unpaired electrons because oxidation state of Fe is 0

so √4(4+2)= 4.9BM

Fe(CN)6 , FE has 6 O.S so number of unpaired electrons =0

u=0

Please mark me Brainliest and follow