Math, asked by maan76753, 11 months ago

The calendar of 2021 will repeat after some years in a specific pattern. What will be that pattern?

After 6, 5, 6, and 11 years

After 4, 8, 4, and 12 years

After 6, 6, 11, and 5 years

After every 7 years

Answers

Answered by rashmitachoudhary565
2

Answer:

after 7 years

Step-by-step explanation:

i am not sure about this answer.please wait till another answer.

Answered by RvChaudharY50
7

Question :- The calendar of 2021 will repeat after some years in a specific pattern. What will be that pattern ?

Answer :-

Concept :- Divide the last two digit of the year by 4.

  • if Remainder 1 = calander will repeat after 6 years.
  • if Remainder 2 = calander will repeat after 6 years.
  • if Remainder 3 = calander will repeat after 11 years.
  • if Remainder 0 = calander will repeat after 5 years.

Example :-

  • 2009 = (09/4) = 1 Remainder = 2009 + 6 = 2015 calander will be same.
  • 1991 = (91/4) = 3 Remainder = 1991 + 11 = 2002 calander will be same.
  • 1784 = (84/4) = 0 Remainder = 1784 + 5 = 1789 calander will be same.

Now,

2021 = (21/4) = 1 Remainder .

Therefore,

→ 2021 + 6 = 2027 calander will be same.

Now,

→ 2027 = (27/4) = 3 Remainder .

Therefore,

→ 2027 + 11 = 2038 calander will be same.

Now ,

→ 2038 = (38/4) = 2 Remainder .

Therefore,

→ 2038 + 6 = 2044 calander will be same.

Now,

→ 2044 = (44/4) = 0 Remainder .

Therefore,

→ 2044 + 5 = 2049 calander will be same.

Hence, Correct Pattern will be 6, 11, 6, and 5 years .


amitnrw: if Remainder 2 = calendar will not repeat after 6 years as year with remainder 2 is not leap year while year after 6 years of that will be a leap year.
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