Question

The calorific value of a rocket fuel is 240 J g?. Calculate the power developed in Kilowatts, if the
rocket consumes 500 g of fuel per minute.
or Answer 2kw
​

Answer 1

Explanation:

cv=240j/g or 240kj/kg

cv=heat/amount of fuel

gn

dm/dt=500g/60s

m=500×10^-3kg

cv=h/m

h(or)e=240×(50×10^-3)

power=e/t

=e÷60 sec

=2 kilojoules

1kwh=3.6 × 10^6joules

so now calculate kwh

Answer 2

Answer:

for 1g= 240j work is to be done by the fuel

for 500g=240j*500

             =120000j work is to be done by the fuel in one minute

then power=120000j/60s

                  =2000watt or 2kw

Explanation: