the calue of (1+i)^10
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Answer:First write this complex number in polar form and then apply De Moivre :
(
1
−
i
)
10
=
(
√
2
∠
−
π
4
)
10
=
[
√
2
(
cos
(
−
π
4
)
+
i
sin
(
−
π
4
)
)
]
10
=
(
√
2
)
10
[
cos
(
−
10
π
4
)
+
i
sin
(
−
10
π
4
)
]
=
−
32
i
Step-by-step explanation:please mark me brainlist???
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