The capacitance of a capacitor is 3 uF. if a charge of 108 uC exists on it, claculate its potential
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Question:
The capacitance of a capacitor is 3 μF. If a charge of 108 μC exists on it, claculate its potential.
Answer:
Potential of the capacitor is 36 V.
Explanation:
Given:
- Capacitance of the capacitor (C) = 3 μF.
- Charge on the capacitor (q) = 108 μC.
To find:
Potential of the capacitor (V).
Solution:
We know that,
V = q/C
= (108 mC)/(3 mF) = 36 V
This is the required answer.
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