Question

The capacitance of a parallel parallel plate capacitor having air between its plates stand if the distance between the plate is reduced to half and the medium between plate is replaced by a medium of dielectric constant k is equal to 5 then find out the value of how much increase and decrease in the capacitance of the

Answer 1

Answer:

Here

K=10pF K=4 C

1

=

d

ε

0

A

=10μF...(i)

and C

2

=K

d/2

ε

0

A

=

d

4×2ε

0

A

=8×10=80pF (Using (i))

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