Question

The capacitance of a parallel plate capacitor having air
between its plates is 10 µf if the distance between the plates is

reduced to half and the medium between plates is replaced by

a medium of dielectric constant k=5, then find the value how

much increase or decrease in the capacitance of the capacitor.​

Answer 1

Answer:

Here

K=10pF K=4 C

1

=

d

ε

0

A

=10μF...(i)

and C

2

=K

d/2

ε

0

A

=

d

4×2ε

0

A

=8×10=80pF (Using (i))

I HOPE IT HELP YOU!