The capacitance of a parallel plate capacitor is 10 uF when distance between its plates is 8 cm. If distance between the plates is reduced to 4 cm, its capacitance will be- (1) 5 uF (2) 10 uF (3) 20 uF (4) 40 uF
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The capacitance of parallel plate capacitor is C=Aϵ0/d. where A= area of plate.
Thus, C∝1/d
If d is halved then the capacitance will be doubled.
Hence the capacitance becomes C′=2C=2(10)=20μF
option C is correct
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