Question

The capacitance of air capacitor is C. If three dielectrics of same thickness and dielectric constants 2,4,6 are placed between the plates the capacitance now will be

Answer 1

Answer:

Original value of parallel plate capacitance   Co=dAϵo

Let the dielectric constant of material be  K.

Capacitance of capacitor with material  C1=d/2KAϵo

Capacitance of capacitor without material  C2=d/2Aϵo

Equivalent capacitance of series combination  Ceq=C1+C2C1C2=K+12KdAϵo=K+12KCo

Given,   Ceq=34Co

∴  We get   K+12K=34

⟹ K=2