The capacitance of an ideal capacitor is 2 uf. What is its reactance if the frequency of the applied alternating EMF is 1000 Hz
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Answer:
Reactance = 1/WC
Therefore, Xc = 1/(2π1000 × 2 × 10^-6)
Therefore Xc = 1000/4π
Therefore, Xc = 79.6
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