Physics, asked by pramitmeshram, 7 months ago

The capacitance of the capacitor is increased by a factor equal to the ratio of the electric field without the dielectric to that with the dielectric

Answers

Answered by Rishi2026
0

Answer:A capacitor is a device used to store electric charge. Capacitors have applications ranging from filtering static out of radio reception to energy storage in heart defibrillators. Typically, commercial capacitors have two conducting parts close to one another, but not touching, such as those in Figure 1. (Most of the time an insulator is used between the two plates to provide separation—see the discussion on dielectrics below.) When battery terminals are connected to an initially uncharged capacitor, equal amounts of positive and negative charge, +Q and –Q, are separated into its two plates. The capacitor remains neutral overall, but we refer to it as storing a charge Q in this circumstance.

The previous example highlights the difficulty of storing a large amount of charge in capacitors. If d is made smaller to produce a larger capacitance, then the maximum voltage must be reduced proportionally to avoid breakdown (since  

E

=

V

d

). An important solution to this difficulty is to put an insulating material, called a dielectric, between the plates of a capacitor and allow d to be as small as possible. Not only does the smaller d make the capacitance greater, but many insulators can withstand greater electric fields than air before breaking down.

There is another benefit to using a dielectric in a capacitor. Depending on the material used, the capacitance is greater than that given by the equation  

C

=

κ

ϵ

0

A

d

by a factor κ, called the dielectric constant. A parallel plate capacitor with a dielectric between its plates has a capacitance given by  

C

=

κ

ϵ

0

A

d

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