Question

The capacitor of capacitance 4 muF and 6 muF are connected in series. A potential difference of 500 volts applied to the outer plates of the two capacitor system. Then the charge on each capacitor is numerically

Answer 1

Answer:

10 × 10^-4 C

Explanation:

in series capactance

1/Cs= 1/C¹ +1/C²...

here

1/C'= 1/4 + 1/6

C'= 2.4 muF

=2.4 ×10^-6F

also as we know

Q=CV

= 2.4×10^-6 ×500

=12×10^-4coulomb..

Hope it helps you..