Question

The capacity of a CD ROM is 800 MB (8.0 × 108 bytes). It stores information along a spiral track. If each byte uses space or 9 microns, what is the length of the complete track in metres? ( hint: 1 micron = 10–6m)

Please answer this question

Answer 1

Answer:

1234468904u747582020

Answer 2

Answer:

72 × $10^{2}$m

Step-by-step explanation:

Capacity = 800MB = 8 × $10^{8}$m

1 byte = 9 microns = 9 × $10^{-6}$m

∴ Total length =  (8 × $10^{8}$) × (9 × $10^{-6}$)

= (8 × 9) × ($10^{8}$ ×  $10^{-6}$)

= 72 × $10^{8-6}$

= 72 × $10^{2}$m

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