Question

The capacity of a CD ROM is 800 MB (8.0 × 108 bytes). It stores information along a spiral track. If each byte uses a space or 9 microns, what is the length of the complete track in metre?
( hint: 1 micron = 10–6m)

Answer 1

Answer:

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Step-by-step explanation:

please mark me as brainlist

Answer 2

Answer:

72*10^-4*2^20m

Step-by-step explanation:

capacity of cd-rom =

1 byte = 9 microes

1 micron = 10^-6 m

9 microns = 9×10 ^-6 m

800 x 20⁰ bytes = 800 x 2^20 x 9 x 10^-6

= 7200 x 2^20 x 10^-6

==> 72*10^2*2^20*10^-6

72*10^-4*2^20m