Math, asked by farzana50, 1 year ago

the capacity of a closed cylindrical vessel is of height 2m is 77m3 (cube). find the radius of the vessel.​

Answers

Answered by prasad0000
0
volume \: of \: cylinder = \pi \times {r}^{2} h hence 77=2×r×r
R×r=77/2
Answered by Anonymous
8
✔️Given,.

Capacity of the closed cylindrical vessel = 77{m}^{3}

Height of the vessel = 2m

Let the radius of the vessel be 'r'.

Capacity of the vessel = volume of the vessel

We know that,

Volume of the cylinder = π{r}^{2}h

Putting the volume and the given height in their respective places.

77{m}^{3}= 22/7 × {r}^{2} × 2m

77{m}^{3}× 7 / 2m×22 = {r}^{2}

49/4 {m}^{2} = {r}^{2}

r = √49/4{m}^{2}

r = 7/2 m

✔️Verification:

Volume of the vessel = π{r}^{2}h

= 22/7 × 7/2 × 7/2 × 2

= 77{m}^{3}

Therefore, the radius of the vessel is 7/2 m.

farzana50: thnx..
Anonymous: My plsr dear
farzana50: hmmm.....
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