Question

The capacity of a closed cylindrical vessel of height 1m is15.4liter how many m2 of metal sheet would needed to make it

Answer 1

15.4=22/7*r*r*1
15.4*7=22*r*r
107.8=22*r*r
${r}^{2} = 107.8 \div 22$
${r}^{2} = 4.9$
$\sqrt{r = .7}$

Answer 2

$\huge{\underline{\sf{\green{Solution-}}}}$

$\underline\green{\sf Given -}$

• $\longrightarrow \sf{h = 1m}$

• $\longrightarrow \sf{Volume = 15.4 l}$

$\underline\green{\sf Find -}$ TSA?

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Volume of Cylinder = $\huge{\underline{\sf{\green{\pi{r}^{2}h}}}}$

$\longrightarrow \sf{\pi{r}^{2}h \: = \: 1.54\times1000}$

$\longrightarrow \sf{= \dfrac{22}{7}\times{r}^{2}\times(100) = 1.54\times1000}$

$\longrightarrow \sf{{r}^{2} = \dfrac{1.54 \: \times \: 1000 \: \times 7} {22 \: \times 100}}$

$\longrightarrow \sf{{r}^{2}= 49}$

$\longrightarrow \sf{r = \sqrt{49}}$

$\longrightarrow \sf\green{r = 7cm}$

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TSA of cylinder = $\huge{\underline{\sf{\green{2 \pi r(r+h)}}}}$

$\longrightarrow \sf{=2\times\dfrac{22}{7}(7+100)}$

$\longrightarrow \sf{=44\times107}$

$\longrightarrow \sf\green{= 4708{cm}^{2}}$

• $: 4708{cm}^{2} = ?{m}{2}$

$\longrightarrow \sf{\dfrac{4708}{100\times100}{m}^{2}}$

$\longrightarrow \sf\green{ = 0.4708{m}^{2}}$

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