Question

The capacity of a closed cylindrical vessel of height 1m is15.4liter how many m2 of metal sheet would needed to make it?​

Answer 1

$\huge\mathcal{\boxed{\fcolorbox{lime}{yellow}{SOLUTION}}}$

☃️ Height of the vessel = 1m

☃️ Capacity of the vessel = 15.4 liters

• 15.4 L = 0.0154 m³

⭐ Volume of the cylindrical vessel = π r² h

→ 0.0154 = 22/7 × r² × 1

→ r² = 0.0049

→ r = 0.07 m

✨ Metal sheet needed to make the cylindrical vessel = T.S.A of the cylindrical vessel .

$\bf{\implies\:2\:\pi\:r\:(r\:+\:h)\:}$

$\bf{\implies\:2\times{\dfrac{22}{7}}\times{0.07}\:(0.07\:+\:1)\:}$

$\bf\green{\implies\:0.4708\:m^2}$

∴ 0.4708m² of sheet will be required to make the vessel .

Answer 2

Answer:

☃️ Height of the vessel = 1m

☃️ Capacity of the vessel = 15.4 liters

15.4 L = 0.0154 m³

⭐ Volume of the cylindrical vessel = π r² h

→ 0.0154 = 22/7 × r² × 1

→ r² = 0.0049

→ r = 0.07 m

✨ Metal sheet needed to make the cylindrical vessel = T.S.A of the cylindrical vessel .

\begin{gathered}\bf{\implies\:2\:\pi\:r\:(r\:+\:h)\:} \\ \end{gathered}

⟹2πr(r+h)

\begin{gathered}\bf{\implies\:2\times{\dfrac{22}{7}}\times{0.07}\:(0.07\:+\:1)\:} \\ \end{gathered}

⟹2×

7

22

×0.07(0.07+1)

\begin{gathered}\bf\green{\implies\:0.4708\:m^2} \\ \end{gathered}

⟹0.4708m

2

∴ 0.4708m² of sheet will be required to make the vessel .

Step-by-step explanation:

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