The capacity of a closed cylindrical vessel of height 1m is15.4liter how many m2 of metal sheet would needed to make it?
Answers
Answer:
⟶πr
2
h=1.54×1000
\longrightarrow \sf{= \dfrac{22}{7}\times{r}^{2}\times(100) = 1.54\times1000}⟶=
7
22
×r
2
×(100)=1.54×1000
\longrightarrow \sf{{r}^{2} = \dfrac{1.54 \: \times \: 1000 \: \times 7} {22 \: \times 100}}⟶r
2
=
22×100
1.54×1000×7
\longrightarrow \sf{{r}^{2}= 49}⟶r
2
=49
\longrightarrow \sf{r = \sqrt{49}}⟶r=
49
\longrightarrow \sf\green{r = 7cm}⟶r=7cm
___________________________________
TSA of cylinder =\huge{\underline{\sf{\green{2 \pi r(r+h)}}}}
2πr(r+h)
\longrightarrow \sf{=2\times\dfrac{22}{7}(7+100)}⟶=2×
7
22
(7+100)
\longrightarrow \sf{=44\times107}⟶=44×107
\longrightarrow \sf\green{= 4708{cm}^{2}}⟶=4708cm
2
{: 4708{cm}^{2} = ?{m}{2}:4708cm}:4708cm
2
=?m2:4708cm
\longrightarrow \sf{\dfrac{4708}{100\times100}{m}^{2}}⟶
100×100
4708
m
2
\longrightarrow \sf\green{ = 0.4708{m}^{2}}⟶=0.4708m
2