The capacity of a closed cylindrical vessel of height Im is 19.8 litres. How many square metres of metal sheet would be needed to make it?
Answers
Given: The capacity of a closed cylindrical vessel of height 1 m is 19.8 litres.
To find: How many square metres of metal sheet would be needed to make it?
Solution:
- Now we have given capacity of a closed cylindrical vessel of height Im is 19.8 litres.
Volume = capacity of vessel
V = 19.8 litres
V = 19.8 x 1/1000 m³
V = 19.8/1000 m³
- Now volume of cylinder is πr²h, so:
πr²h = 19.8/1000
22/7 x r² x 1 = 19.8 / 1000
r² = 19.8 x 7 / 1000 x 22
r² = 0.9 x 7 / 1000
r² = 6.3 / 1000
r = √63 / 10000
r = √0.0063
r = 0.0793 m
- Now total surface area of cylinder is: 2πr(r + h)
TSA = 2 x 22/7 x 0.0793(0.0793 + 1)
TSA = 44/7 x 0.0793 (1.0793)
TSA = 44/7 x 0.0793 (1.0793)
TSA = 44/7 x( 0.08558)
TSA = 0.53 m²
Answer:
So the total sheet required is 0.53 m².
Answer:
Given: The capacity of a closed cylindrical vessel of height 1 m is 19.8 litres.
To find: How many square metres of metal sheet would be needed to make it?
Solution:
Now we have given capacity of a closed cylindrical vessel of height Im is 19.8 litres.
Volume = capacity of vessel
V = 19.8 litres
V = 19.8 x 1/1000 m³
V = 19.8/1000 m³
Now volume of cylinder is πr²h, so:
πr²h = 19.8/1000
22/7 x r² x 1 = 19.8 / 1000
r² = 19.8 x 7 / 1000 x 22
r² = 0.9 x 7 / 1000
r² = 6.3 / 1000
r = √63 / 10000
r = √0.0063
r = 0.0793 m
Now total surface area of cylinder is: 2πr(r + h)
TSA = 2 x 22/7 x 0.0793(0.0793 + 1)
TSA = 44/7 x 0.0793 (1.0793)
TSA = 44/7 x 0.0793 (1.0793)
TSA = 44/7 x( 0.08558)
TSA = 0.53 m²
Answer:
So the total sheet required is 0.53 m².
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