Math, asked by jassv6210, 11 months ago

The capacity of a cylindrical tank is 246.4 litres. If its height is 4 metres, what is the diameter of the base of the tank?

Answers

Answered by ANGELNIVI
11
Volume of the tank =  246.4 litres =  246400 cm^3

Let the  radius of the base be r cm . Then ,

(22/7 xx r^2 xx 400) = 246400

hArr    r^2 = ((246400 xx 7)/(22 xx 400))

hArr   r^2 =  196          hArr   r = 14

:.    Diameer of the base = 2r =  28 cm.

Answered by Raghav1330
1

The diameter of the base of the tank is 0.28m.

Given:

The capacity of a cylindrical tank is 246.4 liters.

The height of the tank is 4 meters.

To Find:

Diameter of the base of the tank.

Solution:

Here, it is given that the volume of the cylindrical tank is 246.4L.

we know that, volume =\pi r^{2}h.

Let's suppose that the radius is r.

now,

\frac{246.4}{1000} =\frac{22}{7}\times r^{2}\times 4

here, r^{2}=\frac{246.4\times 7}{22\times 4\times 1000}

now, after calculating the above equation, we get,

r=\sqrt{0.0196}\\ =0.14m

here, the diameter of the base =2\times r

                                                  =0.14\times 2\\=0.28m

Hence, the diameter of the base of the tank is 0.28m.

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