Question

The capacity of a parallel plate capacitor formed by the plates of same are A is 0.02μF with air as dielectric. Now one plate is replaced by a plate of area 2A and dielectric (K = 2) is introduced between the plates, the capacity is​

Answer 1

Answer:

0.08uF

Explanation:

C=e0erA/d. er= K= 1 for air

C becomes 4 times

C is directly proportional to A and dielectric constant

A---->2A

K........>2

C...... >4C

4*.02=.08

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Answer 2

Answer:

0.04muF

Explanation:

formula: c=ke0A/d

reason:

Area of one of the plate is made by 2A and a dielectric is introduced then if we consider the area of smaller plate then there will be no change in area

c'= ke0A/d

k=2

c'=2c

c'=2×0.02muF

c'= 0.04muF