Question

The capacity of a parallel plate capacitor is 10 μF when the distance between its plates

is 9 cm. What will be its capacity if the distance between the plates is reduced by 6 cm.

i need solution of this problem please ​

Answer 1

Answer:

The capacitance of parallel plate capacitor is C=dAϵ0. where A= area of plate. 

Thus, C∝d1

If d is halved then the capacitance will be doubled.

Hence the capacitance becomes C′=2C=2(10)=20μF

Explanation:

I hope it will help u

Answer 2

The capacitance of parallel plate capacitor is C=

d

Aϵ

0

. where A= area of plate.

Thus, C∝

d

1

If d is halved then the capacitance will be doubled.

Hence the capacitance becomes C

′

=2C=2(10)=20μF

Explanation: