Question

The capacity of a parallel plate capacitor of each plate area of 10cm × 10cm and separated by a distance 1 mm

Answer 1

Answer:

100 CM is the capacity of capacitor

Answer 2

Answer:

$\bigstar{\bold{Capacity\:=\:8.854\times 10^{-12} \:F}}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Area of plate(A)  = 10 cm²=10×10⁻⁴ m²
• Distance (D)= 1 mm = 10⁻³ m

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Capacity of the capacitor(C)

$\Large{\underline{\underline{\bf{Solution:}}}}$

$\dag$ The capacity of the capacitor is given by the formula

  $C\:=\:\dfrac{A\epsilon_0}{D}$

  where $\epsilon_0$ = 8.854×10⁻¹² F/m

$\dag$ Substituting the datas, we get

 $C\:=\:\dfrac{10\times 10^{-4}\times 8.854\times 10^{-12} }{10^{-3} }$

 $C\:=\:8.854\times 10^{-12} \:F$

 $\boxed{\bold{Capacity\:=\:8.854\times 10^{-12} \:F}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

$\dag$ Capacitance depends on permittivity of medium between the plates

$\dag$ Capacitance is inversely proportional to distance between the plates

  $C\propto\dfrac{1}{D}$

$\dag$ The unit of capacitance is Farad (F)