Question

The capacity of a parallel plate capacitor with air is 18 pF. When a dielectric material is

inserted in the space between the plates, its capacity becomes 108 pF. Calculate the permittivity

of the material. What is the material?​

Answer 1

Answer:

Explanation:

Answer

Capacitance is given by:

C=  

d

Kε  

o

​

A

​

 

K  

′

=5  

d  

′

=d/2

⟹C  

′

=10C=80 pF

Answer 2

Explanation:

The air filled capacitance , C=

d

Aϵ

0

=9pF

According to question there are two capacitor with capacitances C

1

and C

2

. and they are in series .

Here, C

1

=

(d/3)

Ak

1

ϵ

0

=9

d

Aϵ

0

=9C as k

1

=3

and C

2

=

(2d/3)

Ak

2

ϵ

0

=9

d

Aϵ

0

=9C as k

2

=6

The equivalent capacitance, C

eq

=

C

1

+C

2

C

1

C

2

=

9C+9C

(9C)(9C)

=

2

9

C=(9/2)9=40.5pF

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