Question

The capacity of a parking place is of 90 cars. At a particular time, 3/5 of the parking place is occupied. How many more cars can be parked at that time?​

Answer 1

ANSWER:

Given:

• Capacity of a parking place = 90cars
• Place occupied at a certain time = 3/5

To Find:

• No of cars that can be parked at that time.

Solution:

We have,

⇒ Total capacity = 90cars

⇒ Place Occupied = 3/5

So, to find the number of cars that can be parked more, we have two options. First method, is to find the number of cars present, and then subtract it from 90. And the second method is that, we will subtract 3/5 from 1(or 5/5) and then multiply it with 90.

In either case, the answer will be same.

We will do both methods.

Method 1:

⇒ Place Occupied = 3/5

⇒ No of cars present = 3/5 × 90

⇒ No of cars present = 3 × 18

⇒ No of cars present = 54.

So,

⇒ No. of cars that can be parked = 90 - 54

⇒ No. of cars that can be parked = 36

Method 2:

⇒ Place Occupied = 3/5

⇒ Place Left = 1 - 3/5

⇒ Place Left = 5/5 - 3/5

⇒ Place Left = 2/5

So,

⇒ No. of cars that can be parked = 2/5 × 90

⇒ No. of cars that can be parked = 2 × 18

⇒ No. of cars that can be parked = 36

Therefore, the total number of cars that can be parked more is 36.