Question

The capacity of big drop formed by 125 drops each of capacity5uf will be

Answer 1

Given:

125 drops

Capacity of each drop = 5 μf

To find:

The capacity of the big drop.

Solution:

To find the volume of the bid drop,

Volume of the big drop = 125 * volume of small drop

Volume = 4 / 3 * π * radius^3

Hence,

125 * 4 / 3 * π * radius^3

Here,

The big drop capacitance = 5 * capacitance of small drops

5 x 5

We get,

Capacity of big drop = 25 μf

Hence, The capacity of big drop formed by 125 drops each of capacity 5 μf will be 25 μf

Answer 2

The actual answer is, “The capacity of big drop formed by 125 drops each of capacity 5uf will be 25uf.”

The total volume of the big drop = 125 * volume of the small drop

4/3 pi * r^3 = 125 * 4/3 pi * R^3

r^3 = 125 * R^3

taking cube root on both side

r = 5 * R

then capacitance for big = 5* capacitance for small

= 5 * 5 = 25uf