Question

The capacity of closed cylindrical vessel is 26.4l. It's height is 84cm. how many sq m of metal sheet required to make it??? Pls help. Hi gain points but pls ans​

Answer 1

Given :

Capacity of the closed cylindrical vessel = 26.4 litres

Convert the capacity to cm³

We know that

1 litre = 1000 cm³

26.4 litres = 26.4 × 1000 = 26400 cm³

Capacity of the cylindrical vessel = 26400 cm³

Capacity is nothing but volume

So, Volume of the cylindrical vessel = 26400 cm³

Given :

Height of the cylindrical vessel = 84 cm

Let the Radius of the cylindrical vessel be ' r 'cm

Volume of the cylindrical vessel = πr²h cu.units

⇒ 26400 = 22/7 × r² × 84

⇒ 26400 = 22 × r² × 12

⇒ 26400 = 264r²

⇒ r² = 100

⇒ r = 10

So, Radius of the cylindrical vessel = 10 cm

Area of metal sheet required to make cylindrical vessel = TSA of cylindrical vessel

= 2πr( r + h ) sq.units

= 2 × 3.14 × 10 ( 10 + 84 )

= 62.8 × 94

= 5903.2 cm² ( approx)

Therefore the area of metal sheet required to make cylindrical vessel is 5903.2 cm².

Answer 2

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QUESTION :

The capacity of closed cylindrical vessel is 26.4l.

It's height is 84cm.

how many sq m of metal sheet required to make it???

SOLUTION :

We know that the volume of the vessel is equal to π r^2 h.

Given :

V = 26.4 L = 26400 cm^3

H = 84 cm.

Substituting the above values in the formula for the volume,

We get r = 10 cm.

Now we know that :

"" how many sq m of metal sheet required to make it??? "" refers to the T.S.A of the vessel.

TSA = π r h( h + r ) = 5904.2 cm^2

________

Calculation :

26400 = π r^2 64

=> 26400 = 22 r^2 12

=> 26400 = 264 r^2

=> r^2 = 100

=> r = 10 cm.

π 10 64 ( 10 + 64 )

=> 640 π 74 = 5904.2 cm^2.