Question

The capacity of one cylinder is 4 dm^3 and that of other cylinder is 1 dm^3; the pressure in the second cylinder is 560 mm Hg and that in the second 1000 mm Hg. Both of the cylinder contain co2 connected by a pipe with the tap.what will be the final pressure??

Answer 1

Apply Charles law(Or was it Boyle's, Lol I forgot :P)

Anyways so yeah,

P¹V¹=P²V² (¹, ² are actually in sub script)

Lol naah wait, I read the sum wrong.....

The pressure will be the same in both the jars when connected,

Therefore P¹V¹+P²V²= P(final)×V(total)

So, 4×560+ 1×1000=P×5

3240/5=P

648 mm of Hg (Hope that's the answer, lol)

Anyways, have a great day ahead and see you around

peace

Answer 2

It is stated that,

Pressure of the first cylinder before fill up with gas (p1)= 560 mm Hg

Capacitance of the first cylinder before fill up with gas(v1) = 4 dm³

Pressure after obtaining the gas(p2) = p2

Capacitance after obtaining the gas(v2)= 5 dm³

Pressure in the second cylinder before obtaining the gas(p3)=1000

Capacitance before filling with gas(v3)= 1 dm³

Pressure in the second cylinder after filling with gas (p4)=p4

Capacitance of the second cylinder after filling with gas (v4)= 5 dm³

Now, for the first cylinder_

From the relationship we get,

p1v1=p2v2

or, 560*4=p2*5

or, p2 = 560*4/5

or, p2 = 112*4

or, p2 =448 mm Hg

Now for the second cylinder_

From the relationship we get,

p3v3=p4v4

or, 1000*1=p4*5

or, p4 = 1000/5

or, p4 = 200 mm Hg

So, total pressure exerted =(448+200) mm Hg

                                            = 648 mm Hg