Math, asked by msaidi1088, 1 month ago

The capacity of
water tank is 200 kn
kilotitres .On
the first day 84 kilolitres 950
lifter of Water was
drained out.
How much
water remained in the tank ? (Express in Litre)​

Answers

Answered by ZzyetozWolFF
82

Correct Question:

The capacity of a water tank is 200 kilolitres. On the first day, 84 kilolitres 950 litres of water was drained out. How much water remained in the tank? ( Express in litres.)

Answer:

1,15,050 litres of water was left.

Step-by-step explanation:

Capacity = 200kl

Drained out = 84kl 950l

Remaining =?

Converting to litres -

Unit - 1kl = 1000l

=> 200 × 1000 = 2,00,000 litres

=> 84kl 850l = 84,000 + 950 = 84,950 litres.

Remaining = 2,00,000 - 84,950 = 1,15,050 litres.

Answered by BrainlyRish
42

Given that, The capacity of water tank is 200 kilolitres .On the first day 84 kilolitres 950 liter of Water was drained out .

Exigency To Find : The Remained Water in tank ??

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀¤ Finding out The Remained Water in tank :

Given that ,

  • The capacity of water tank is 200 kilolitres .

⠀⠀⠀⠀⠀Converting the units from kilolitres to litres :

\qquad \dashrightarrow \sf Capacity_{(Tank)} \:=\: 200 \:kilolitres \: \:\\\\\qquad \dashrightarrow \sf Capacity_{(Tank)} \:=\: 200 \:\times 1000 \: \:litres \:\qquad \:\:\bigg\lgroup \sf{ 1 \:kilolitres  \:=\:1000 \:litres}\bigg\rgroup\:\\\\\qquad \dashrightarrow \sf Capacity_{(Tank)} \:=\: 200000 \:litres \: \:\\\\\qquad \dashrightarrow \underline {\boxed{\pmb{\frak { \purple{ Capacity_{(Tank)} \:=\: 200000 \:litres \: \:\:\:}}}}}\\\\

⠀⠀⠀⠀⠀AND ,

  • On the first day 84 kilolitres 950 liter of Water was drained out .

⠀⠀⠀⠀⠀Converting the units from kilolitres to litres :

\qquad \dashrightarrow \sf Drained\:water\:_{(Tank)} \:=\: 84 \:kilolitres + 950 \:litres \: \:\\\\\qquad \dashrightarrow \sf Drained\:water\:_{(Tank)} \:=\: 84 \:\times 1000 \: \:litres + \:950 \:litres\qquad \:\:\bigg\lgroup \sf{ 1 \:kilolitres  \:=\:1000 \:litres}\bigg\rgroup\:\\\\\qquad \dashrightarrow \sf  \:Drained\:water\:_{(Tank)} \:=\: 84000 \: \:litres + \:950 \:litres \:\\\\\qquad \dashrightarrow \sf  \:Drained\:water\:_{(Tank)} \:=\: 84950 \:litres \:\\\\\qquad \dashrightarrow \underline {\boxed{\pmb{\frak { \purple{  \: \:Drained\:water\:_{(Tank)} \:=\: 84950 \:litres\: \:\:\:}}}}}\\\\

As , We know that ,

\qquad \dag\:\:\bigg\lgroup \sf{ Remained _{(Water)} \:=\:Capacity_{(Tank)}   \: -\:Drained\:water\:_{(Tank)}\:}\bigg\rgroup \\\\

\qquad \dashrightarrow \sf Remained _{(Water)} \:=\:Capacity_{(Tank)}   \: -\:Drained\:water\:_{(Tank)} \:\\\\

⠀⠀⠀⠀⠀⠀\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\\\\qquad \dashrightarrow \sf Remained _{(Water)} \:=\:Capacity_{(Tank)}   \: -\:Drained\:water\:_{(Tank)} \:\\\\\qquad \dashrightarrow \sf Remained _{(Water)} \:=\:200000  \:litres \: -\:84950\:litres \:\\\\\qquad \dashrightarrow \sf Remained _{(Water)} \:=\:115050\:litres \:\\\\\qquad \dashrightarrow \underline {\boxed{\pmb{\frak { \purple{  \:  Remained _{(Water)} \:=\:115050\:litres\:\:\:}}}}}\\\\

\qquad \therefore \underline {\sf Hence,  \:The \:Remained \:water \:in \:tank\:is \:\pmb{\bf \:115050\:litres \:}.}\\\\

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