Question

the capastiance of capacitor is 10uf and potential
difference is 2 volt then charge stored in
​

Answer 1

Answer:

500μJ

Given : C=10μF=10

−5

F V=10 volts

Energy stored E=

2

1

CV

2

∴ E=

2

1

×10

−5

×10

2

=5×10

−4

J

⟹ E=500μJ

Explanation:

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