Physics, asked by yashasvi3750, 1 year ago

The capicity of big drop formed by 125 drops each of capacity 5uf will be

Answers

Answered by shubhamjoshi033
3

We first find volume of big drop

volume of big drop=125 x volume of small drop

4/3pi.R^3=125 x 4/3pi.r^3

R=5r

because capacitance of solid spherical body directly proportion to radius

hence big drop capacitance =5 x capacitance of small

=5 x 5

capacitance of big drop=25uf


Answered by topanswers
3

Given:

125 drops

Capacity of each drop = 5 μf

To find:

The capacity of the big drop.

Solution:

To find the volume of the bid drop,

Volume of the big drop = 125 * volume of small drop

Volume = 4 / 3 * π * radius^3  

Hence,

125 * 4 / 3 * π * radius^3  

Here,

The big drop capacitance = 5 * capacitance of small drops

5 x 5

We get,

Capacity of big drop = 25 μf

Hence, The capacity of big drop formed by 125 drops each of capacity 5 μf will be 25 μf

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