The capicity of big drop formed by 125 drops each of capacity 5uf will be
Answers
We first find volume of big drop
volume of big drop=125 x volume of small drop
4/3pi.R^3=125 x 4/3pi.r^3
R=5r
because capacitance of solid spherical body directly proportion to radius
hence big drop capacitance =5 x capacitance of small
=5 x 5
capacitance of big drop=25uf
Given:
125 drops
Capacity of each drop = 5 μf
To find:
The capacity of the big drop.
Solution:
To find the volume of the bid drop,
Volume of the big drop = 125 * volume of small drop
Volume = 4 / 3 * π * radius^3
Hence,
125 * 4 / 3 * π * radius^3
Here,
The big drop capacitance = 5 * capacitance of small drops
5 x 5
We get,
Capacity of big drop = 25 μf
Hence, The capacity of big drop formed by 125 drops each of capacity 5 μf will be 25 μf
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