The car A of mass 1500 kg, travelling at 25 m/s collides with another car B of mass 1000 kg travelling at 15 m/s in the same direction. After collision, the velocity of car A becomes 20m/s. Calculate the velocity of car B after collision.
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Answered by
16
Use conservation of momentum equation
m1u1 + m2u2 = m1v1 + m2v2
v2 = (m1u1 + m2u2 - m1v1) / m2
= [(1500 × 25) + (1000 × 15) - (1500 × 20)] / (1000)
= 22.5 m/s
Velocity of car B after collision is 22.5 m/s
m1u1 + m2u2 = m1v1 + m2v2
v2 = (m1u1 + m2u2 - m1v1) / m2
= [(1500 × 25) + (1000 × 15) - (1500 × 20)] / (1000)
= 22.5 m/s
Velocity of car B after collision is 22.5 m/s
Answered by
7
m1u1+m2u2=m1v1+m2v2
1500×25+1000×15=1500×20+1000×v2
375000+15000=30000+1000v2
390000=30000+1000v2
360000=1000v2
360m/s=v2
1500×25+1000×15=1500×20+1000×v2
375000+15000=30000+1000v2
390000=30000+1000v2
360000=1000v2
360m/s=v2
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