Physics, asked by amritpal95, 10 months ago

the car attains a velocity of 36 km h -1 after starting from rest in 5 seconds find the distance travelled by a car​

Answers

Answered by swati1212
2

Answer:

25m

Explanation:

u=0

v= 36km/hr = 10m/s

t=5s

v=u+at

a = 2 m {s}^{ - 2}

 {v}^{2}  -   {u}^{2}  = 2as

100=2×2×s

s=25m/s

Answered by chaudharyankit8
1

Answer:

given final velocity of car is 36km/h

=10m/s

initial velocity is 0

time=5s

we can find

acceleration=v-u/t

a=10-0/5

acceleration=2m/s^2

by third equation of motion

2as=v^2-u^2

s=v^2-u^2/2a

s=100-0/4

s=25m

distance traveled by car is 25m

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