The car is having with a velocity of 10m/s having mass of what will be the K. E of the car it is velocity is changed to 20m/sec
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Answer:
K.E. will increase 4 times
Explanation:
let K.E. when velocity is 10m/s is =x
let K.E. when velocity is 20m/s is =y
let v1=10m/s
v2= 20m/s
As car is same so mass will be same
x= .5*m*10*10 = 50m
y= .5*m*20*20 = 200m
x/y= 50m/200m
x/y= 1/4
y= 4x
its mean
K.E. will increase 4 times
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