Question

The car is moving from rest from point a to b with velocity 72 km/h and taking time 10 sec time . distance between point a to b is 80 m find Acceleration

Answer is 2m/S2
Answer is correctly pls it's urgent​

Answer 1

Answer:

Acceleration is 2 m/s².

Explanation:

To find : Acceleration of car.

We have,

• Initial velocity, u is 0 km/h.
• Final velocity, v is 72 km/h.
• Time taken, t is 10 sec.
• Distance between point a to b, s is 80 m.

Conversion :

SI unit of velocity/Speed is m/s.

• 72 km/h = (72 × 5)/18 = 20 m/s .

• 0 km/h = 0 m/s .

We know,

• Acceleration = v-u/t

Put all values in formula :

→ Acceleration = 20 - 0/10

→ Acceleration = 20/10

→ Acceleration = 2

Thus,

Acceleration of the car is 2 m/s².

Answer 2

QUESTION:-

The car is moving from rest from point a to b with velocity 72 km/h and taking time 10 sec time . distance between point a to b is 80 m find Acceleration

EXPLANATION:-

• Initial velocity(u)= 0 m/s (AS CAR STARTS FROM REST)

• Final velocity(v)=72 km/hr=20 m/s
• Distance covered(S)=80 m
• Time taken (t)=10 s
• Acceleration(a)=?

Let's apply 1nd equation of motion:-

→v=u+at

→20=0+a10

→20=10a

⇒a=2 m/s²

So the acceleration is 2 m/s²

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