Question

The car is moving from rest from point a to b with velocity 72 km/h and taking time 10 sec time . distance between point a to b is 80 m find Acceleration Answer is 2m/S2 Answer is correctly pls it's urgent​

Answer 1

Given:-

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• The car is moving from rest from point a to b with velocity 72 km/h and taking time 10 sec time . distance between point a to b is 80 m.

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To find:-

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• Acceleration

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Solution:-

Initial Velocity (u) = 0

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Final Velocity (v) = 72km/h

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$= 72 \times \frac{5}{18} = 20m/s \\ \\ \\ \\ \\ \sf \: \color{green}\boxed{ \tt \: Acceleration(a) = \frac{(v - u)}{t} }\\ \\ \\ \\ \\ = \frac{20 - 0}{10} \\ \\ \\ \\ \\ = 2m/s {}^{2}$

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Hence, The Answer is 2m/s²

Answer 2

$\: \: \: \:$

in the given question we have

u=36 km/hr =36×

18

5

m/s=10m/s

v= 72 km/hr=72× 18

m/s=20m/s

t=10 s

a=?

we know the formula

v= u +at

20 = 10+ a 10

20-10 =10 a

10 = 10 a

a = 1 m/s²

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