Question

the car is moving with a velocity 5m/s . when breaks are applied , the bus covers 50m and take 20s to stop.calculate the retardation of the car.​

Answer 1

Given:-

Initial velocity(u)=5m/s

Distance covered(s)=50m

Time taken=20s

To find:-

Retardation of the car(negative acceleration)

Solution:-

By the second equation of motion,we get-----

$s = ut + \frac{1}{2} a {t}^{2}$

$= > 50 = 5 \times 20 + \frac{1}{2}a \times {20}^{2}$

$= > 50 = 100 + 200a$

$= > 50 - 100 = 200a$

$= > - 50 = 200a$

$= > a = \frac{ - 50}{200}$

=> a= -0.25m/s²

Since,acceleration of the car is -0.25m/s²

Thus,retardation is 0.25m/s².

Answer 2

Explanation:

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