the car moving with the velocity of 35 km/h and another car with 19 m/scompare the kinetic energy
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Answer:
ans.3.82
Explanation:
The 1st car was moving with a velocity of 35km/hr.
But,SI unit of velocity is m/s.
Since we can write 35km/hr as 35×5/18=9.72m/s.
Now kinetic energy = 1/2mv^2
=1/2×m×(9.72)² joule.
Now kinetic energy of 2nd car=1/2mv²
=1/2×m×(19)²
On comparing 1 and 2 we get
½m×361
---------------
½m×94.47
= 3.82.
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