the car parking there are 100 vehicle 60 of which 1 hours 30 events and the remainder lorries if each vehicle is equally likely to leave find the probability of a man living 1st BA lawyer living first CA ka living second if I were a lorry Aravan hand left first
Answers
Total vehicles = 100 (Given)
Total cars = 60 (Given)
Total van = 30 (Given)
Total lorries = 100 - 60 - 30 = 10
P(Second vehicle is a car) = P(1st vehicle is a Lorry/van) x P(2nd vehicle is a car)
P(Second vehicle is a car) = (30 + 10)/100 x 60/(100 - 1)
P(Second vehicle is a car) = 8/33
If you need the answer in percentage:
8/33 x 100 = 24.24%
Answer: The probability of a car leaving second is 8/33
Step-by-step explanation:
Answer:
Total vehicles = 100 (Given)
Total cars = 60 (Given)
Total van = 30 (Given)
Total lorries = 100 - 60 - 30 = 10
P(Second vehicle is a car) = P(1st vehicle is a Lorry/van) x P(2nd vehicle is a car)
P(Second vehicle is a car) = (30 + 10)/100 x 60/(100 - 1)
P(Second vehicle is a car) = 8/33
If you need the answer in percentage:
8/33 x 100 = 24.24%
Answer: The probability of a car leaving second is 8/33