the car start 18km/h to 36km/h in 5 sec . calculate acceleration and distance
Answers
Answered by
1
change km/h into m/s
18into5/18=5
36into5/18=10
a=v-u/t
10-5/5
5/5
1 m/s square
18into5/18=5
36into5/18=10
a=v-u/t
10-5/5
5/5
1 m/s square
Answered by
0
Final velocity v = 36km/h = 10 m/s
Initial Velocity u = 18 km/h = 5 m/s
time = 5 sec
From the below formula we can get accelaration
v = u + at
10 = 5 + a*5
5a = 5
a= 1m/s2
distance s=ut + (1/2)at2
s = 5*5 + (0.5)*1*5*5
s= 25 + 12.5
s= 37.5
Therefore accelaration = 1 m/s2 and Distance = 37.5 m
Initial Velocity u = 18 km/h = 5 m/s
time = 5 sec
From the below formula we can get accelaration
v = u + at
10 = 5 + a*5
5a = 5
a= 1m/s2
distance s=ut + (1/2)at2
s = 5*5 + (0.5)*1*5*5
s= 25 + 12.5
s= 37.5
Therefore accelaration = 1 m/s2 and Distance = 37.5 m
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