Physics, asked by Sachinqw9579, 1 year ago

The car was running at a speed of 36kmph and the speed of the car is increased by 4kmph

Answers

Answered by djdilip711
0
Speed of car = 36kmph
new speed of car = 36 + 4 = 40kmph
distance in one second = 40 x 1000 / 60 x 60 = 11.11.. m 
distance with old speed in one second = 36 x 1000 / 60 x 60 = 10 m
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